Question: A dog running in an open field has components of velocity v, = 2.6 m/s and Vy = -1.8 m/s at t, = 10.0 s.

A dog running in an open field has components of velocity v, = 2.6 m/s and Vy = -1.8 m/s at t, = 10.0 s. For the time interval from f, = 10.0 s to 12 = 20.0 s, the average acceleration of the dog has magnitude 0.45 m/s2 and direction 31.00 measured from the + x-axis toward the +y-axis. At f2 = 20.0 s,
(a) What are the x- and y-components of the dog's velocity?
(b) What are the magnitude and direction of the dog's velocity?
(c) Sketch the velocity vectors at I, and 12, How do these two vectors differ?

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