Question: Evaluate the integral by making the given substitution. a. e-x dx, u = -x b. x2 (x3 + 1) dx, u = x3
a. ∫ e-x dx, u = -x
b. ∫ x2 √(x3 + 1) dx, u = x3 +1
c. ∫ cos3θ sin θ dθ, u = cos θ
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a Let u x Then du dx so dx du Thus e x dx e u du e u C e x C Dont forget that it is often ve... View full answer
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