Question: Figure P36.72 shows a thin converging lens for which the radii of curvature are R1 = 9.00 cm and R2 = -11.0 cm. The lens
(a) Assume its focal points F1 and F2 are 5.00 cm from the center of the lens. Determine its index of refraction.
(b) The lens and mirror are 20.0 cm apart, and an object is placed 8.00 cm to the left of the lens. Determine the position of the final image and its magnification as seen by the eye in the figure.
(c) Is the final image inverted or upright? Explain.
Fo Fv
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a b c The lens makers equation 1 500 cm becomes becomes As the light passes through th... View full answer
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