(25 pts) The figure below shows a thin, converging lens, whose radii of curvature are of magnitudes R and R2 11.0 cm. = The lens is in front of a concave spherical mirror with a radius of curvature R = 8.00 cm. = 9.00 cm Assume the focal points F1 and F2 of the lens are 5.00 cm from the center of the lens. The lens and mirror are 20.0 cm apart, and the object is placed 8.00 cm to the left of the lens. (a) Determine the index of refraction of the lens material. HINT: Use the lens-makers' equation: 1 = (n - 1) ( - 1 R. where: n = index of refraction. Also, is R2 positive or negative? HINT: In general, R (or R2) is negative if the center of curvature is in front of the lens. (b) Determine the position of the final image. (c) Find the magnification of the final image. (d) Is the final image inverted or upright? HINT: For this problem, after you find n, you will need to use the thin lens equation and the mirror equation. The image formed by the lens becomes the object for the mirror. Then, the image formed by the mirror becomes the object for the 2nd pass of light thru the lens. Cengage Learning. All Rights Reserved. C F2 F1