Question: Find the energy (in MeV) released when + decay converts sodium 2211Na (atomic mass = 21.994 434 u) into neon (atomic mass = 21.991 383

Find the energy (in MeV) released when β+ decay converts sodium 2211Na (atomic mass = 21.994 434 u) into neon (atomic mass = 21.991 383 u). Notice that the atomic mass for 2211Ne includes the mass of 11 electrons, whereas the atomic mass for 2210Ne includes the mass of only 10 electrons.

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The decrease in mass is 21994 434u 21991383u 5485799 x 10 4 u 5485799 x 10 ... View full answer

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