Following are the data from Exercise 16.51 on bacteria counts, in millions, for different cases from each

Question:

Following are the data from Exercise 16.51 on bacteria counts, in millions, for different cases from each of five strains of cultured Staphylococcus aureus.
Following are the data from Exercise 16.51 on bacteria counts,

a. Use the Kruskal-Wallis test to decide, at the 5% significance level, whether the data provide sufficient evidence to conclude that a difference exists in mean bacteria counts among the five strains of Staphylococcus aureus.
b. The hypothesis test in part (a) was done in Exercise 16.51 by using the one-way ANOVA test. The assumption there is that bacteria counts in the five strains are normally distributed and have equal standard deviations. Presuming that to be true, why is performing a Kruskal-Wallis test to compare the means permissible? In this case, is use of the one-way ANOVA test or the Kruskal-Wallis test better? Explain your answers.

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question
Question Posted: