Question: For any random variable X for which EX2 and E|X| exist, show that P(|X| > 6) does not exceed either EX2/b2 or E|X|/6, where b

For any random variable X for which EX2 and E|X| exist, show that P(|X| > 6) does not exceed either EX2/b2 or E|X|/6, where b is a positive constant. If f(x) = e~x for x > 0, show that one bound is better when b = 3 and the other when b = √2. (Notice Markov's Inequality in Miscellanea 3.8.2.)

Step by Step Solution

3.45 Rating (177 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

The function gx x is a nonnegative function So by Chebychevs Inequality PX b EX... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Document Format (1 attachment)

Word file Icon

941-M-S-P (8619).docx

120 KBs Word File

Students Have Also Explored These Related Statistics Questions!