For the case E = 0 of a particle in a rectangular well of depth V0, the

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For the case E = 0 of a particle in a rectangular well of depth V0, the solution to the SchrÃ¶dinger equation inside the well is (II = ax + b [see the discussion after Eq. (2.19)].
In Eq. 2.19

(a) Use the boundary conditions to find four equations relating the constants a and b to C and G in the equation preceding (2.32).
In Eq. 2.32

(b) Show that if C > 0 (or if C (c) Show that C = 0 gives ( = 0 everywhere. Hence, E = 0 is not allowed.

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Quantum Chemistry

ISBN: 978-0321803450

7th edition

Authors: Ira N. Levine

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Question Posted: May 26, 2016 06:16 AM

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For the case E = 0 of a particle in a rectangular well of depth V0, the

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sin (2m/1

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a From I 0 II 0 II l III l and E 0 we get C b Eq 1 ...View the full answer

Quantum Chemistry

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