Given the following data: P4(s) + 6Cl2(g) 4PCl3(g) H = 1225.6 kJ P4(s) + 5O2(g)
Question:
P4(s) + 6Cl2(g) → 4PCl3(g) ΔH = –1225.6 kJ
P4(s) + 5O2(g) → P4O10(s) ΔH = –2967.3 kJ
PCl3(g) + Cl2(g) → PCl5(g) ΔH = –84.2 kJ
PCl3(g) + ½ O2(g) → Cl3PO(g) ΔH = –285.7 kJ
calculate ΔH for the reaction P4O10(s) + 6PCl5(g) → 10 Cl3PO(g)
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P 4 O 10 P 4 5 O 2 H 29673 kJ 10 PCl 3 5 O ...View the full answer
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