Given the following data P4(s) 6Cl2(g) 4PCl3(g) H 1225 6 kJ P4(s) 5O2(g) P4O10(s) H 2967 3 kJ PCl3(g) Cl2(g) PCl5(g) H 84 2 kJ PCl3(g) O2(g) Cl3PO(g) H 285 7 kJ calculate H for the reaction P4O10(s) 6PCl5(g) 10 Cl3PO(g)

Question: Given the following data: P4(s) + 6Cl2(g) 4PCl3(g) H = 1225.6 kJ P4(s) + 5O2(g) P4O10(s) H = 2967.3 kJ PCl3(g) + Cl2(g)

Given the following data:
P4(s) + 6Cl2(g) → 4PCl3(g) ΔH = –1225.6 kJ
P4(s) + 5O2(g) → P4O10(s) ΔH = –2967.3 kJ
PCl3(g) + Cl2(g) → PCl5(g) ΔH = –84.2 kJ
PCl3(g) + ½ O2(g) → Cl3PO(g) ΔH = –285.7 kJ
calculate ΔH for the reaction P4O10(s) + 6PCl5(g) → 10 Cl3PO(g)

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