Question: Given the function g, prove that g is not one-to-one using the definition of a one-to-one function. a. g(x) = 1 - x2 b. g(x)
a. g(x) = 1 - x2
b. g(x) = 3x2 + 1
c. g(x) = x4 - x2
d. (1x) = 1/x6
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a g1 1 1 2 1 1 0 and g1 1 1 2 1 1 0 so g1 g1 but 1 1 Thus the function ... View full answer
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