Question: A hot-air balloonist, rising vertically with a constant velocity of magnitude 5.00 m/s, releases a sandbag at an instant when the balloon is 40.0 m

A hot-air balloonist, rising vertically with a constant velocity of magnitude 5.00 m/s, releases a sandbag at an instant when the balloon is 40.0 m above the ground (Fig. 2.41). After it is released, the sandbag is in free fall.
(a) Compute the position and velocity of the sandbag at 0.250 s and 1.00 s after its release.
(b) How many seconds after its release will the bag strike the ground?
(c) With what magnitude of velocity does it strike the ground?
(d) What is the greatest height above the ground that the sandbag reaches?
(e) Sketch a,-t, v,-t, and y-t graphs for the motion.

A hot-air balloonist, rising vertically

u=5.00 m/s 40.0 m to ground

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