How much energy is released when a 238U nucleus decays by emitting? (a) An alpha particle and

Question:

How much energy is released when a 238U nucleus decays by emitting?

(a) An alpha particle and

(b) A sequence of neutron, proton, neutron, proton?

(c) Convince yourself both by reasoned argument and by direct calculation that the difference between these two numbers is just the total binding energy of the alphaparticle.

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Fundamentals of Physics

ISBN: 978-0471758013

8th Extended edition

Authors: Jearl Walker, Halliday Resnick

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Question Posted: Feb 19, 2011 04:27 AM

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How much energy is released when a 238U nucleus decays by emitting? (a) An alpha particle and

Question:

238U 238.050 79 u 23U 237.048 73 u 2Pa 236.04891 u 235 Pa 235.045 44 u 234TH 234.043 63 u 4.002 60 u 1.007 83 u "He 1.008 66 u

Step by Step Answer:

a The nuclear reaction is written as 238 U 234 Th He T...View the full answer

Fundamentals of Physics

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