Identify each of the following (C4H10O) isomers on the basis of their 13C NMR spectra: (a)
Question:
(a) δ 31.2 ppm: CH3
δ 68.9 ppm: C
(b) δ 10.0 ppm:
δ 22.7 ppm: CH3
δ 32.0 ppm: CH2
δ 69.2 ppm: CH
(c) δ 18.9 ppm: CH3, area 2
δ 30.8 ppm: CH, area 1
δ 69.4 ppm: CH2, area 1
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a This compound has only two different types of carbons One type of carbon come...View the full answer
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