In each case either prove the result by splitting into cases, or give a counterexample. (a) If
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(a) If n is any integer, then n2 = 4k + 1 for some integer k.
(b) If n is any odd integer, then n2 = 4k + 1 for some integer k.
(c) If n is any integer, n3 - n = 3k for some integer k.
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b The implication here is p q where p is the statement n is any odd integer and q is the ...View the full answer
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