Question: In each case, find T-1 and verify that MDB (T)-1 = MBD(T-1). (a) T: R2 R2, T(a,b) = (a + 2b, 2a + 5b);

In each case, find T-1 and verify that MDB (T)-1 = MBD(T-1).
(a) T: R2 → R2, T(a,b) = (a + 2b, 2a + 5b); B = D = standard
(b) T: R3 → R3 T(a,b,c) = b + c, a + c, a + b);
B = D = standard
(c) T : P2 → R3,T(a + bx + cx2) = a - c,b,2a - c
B = [1,x, x2], D = standard
(d) T : P2 → R3,
T(a + bx + cx2) = (a + b + c, b + c,c);
B = [1,x, x2], D = standard

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