In each case, use the Gram-Schmidt algorithm to find an orthogonal basis of the subspace U, and
Question:
(a) U = span{[l -1 0], [-1 0 1]}; X = [2 1 0]
(b) U = span{[l -1 0 1], [1 1 0 0], [1 1 0 1]}; X = [2 0 3 1]
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a U span11 0 1 0 1 but this basis is not orthogonal ...View the full answer
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