In each case, write X as the sum of a vector in U and a vector in
Question:
(a) X = [2 1 6], U = span{[3 -1 2], [2 0 -3]}
(b) X = [2 0 1 6],
U = span{[l 1 1 1], [ 1 1 -1 -1], [1 -1 1 -1]}
(c) X = [a b c d],
U = span{[l -1 2 0], [-1 1 1 1]}
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a Write e 1 3 1 2 and e 2 2 0 3 Then e 1 e 2 is orthogo...View the full answer
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