Question: In Exercises, (a) find the discriminant b2 - 4ac, and then determine whether one real-number solution, two different real-number solutions, or two different imaginary-number solutions
1. x2 - 3x - 5 = 0
2. 4x2 - 12x + 9 = 0
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1 x 2 3x 5 0 a b 2 4ac 3 2 4 1 5 9 20 29 0 There are two realnumber solutions b x b b 2 ... View full answer
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