In Figure, light is initially in a medium (such as air) of index of refraction n 1

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In Figure, light is initially in a medium (such as air) of index of refraction n1. It is incident at angle θ1 on the surface of a liquid (such as water) of index of refraction n2. The light passes through the layer of water and enters glass of index of refraction n3. If θ3 is the angle of refraction in the glass, show that n1 sin θ1 = nsin θ3. That is, show that the second medium can be neglected when finding the angle of refraction in the third medium.

n2 (n2 > n) n3 (n3 > n)

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