Question: Let A and B be n n is matrices. Show that (a) If is a noniem eigenvalue of AB. then i is also
(a) If λ is a noniem eigenvalue of AB. then i is also an eigenvalue of BA.
(b) If A = 0 is an eigenvalue of Ab, then λ = 0 is also an eigenvalue of BA.
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a If is a nonzero eigenvalue of AB with eigenvector x then let y B x Since A y AB ... View full answer
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