Let A and consider TA : R2 R2. (a) Show that the only eigenvalue of TA
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and consider TA : R2 †’ R2.
(a) Show that the only eigenvalue of TA is A = 0.
(b) Show that ker(TA) = (R)
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is the unique TA-invariant subspace of R2: (except for 0 and R2).
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b First ker T A is T A invariant by Exercise 2 Now suppose that U is any TAinva...View the full answer
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