Question: Let A be a real 5 x 5 matrix, and assume that A has eigenvalues i, - i, -2, - 1 (and no others). Is

Let A be a real 5 x 5 matrix, and assume that A has eigenvalues i, - i, -2, - 1 (and no others). Is the zero solution to the linear system u = A u necessarily stable? Explain. Does your answer change if A is 6 x 6?

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