Let f be C1 and suppose that Df[x0] is one-to-one. Then 1. f is locally one-to-one, that
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1. f is locally one-to-one, that is, there exists a neighborhood S of x0 such that f is one-to-one on S
2. f has an inverse f-1: f(S) → S that is continuous
3. f is locally onto
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1 Since x 0 is continuous and onetoone there exists a constant such that x 1 x 2 x ...View the full answer
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