Question: Let R Z+ Z+ be the relation given by the following recursive definition. 1) (1, 1) R; and 2) For all (a,
1) (1, 1) ∈ R; and
2) For all (a, b) ∈ R, the three ordered pairs (a + 1, b), (a + 1, b + 1), and (a + 1, b + 2) are also in R
Prove that 2a > b for all (a, b) ∈ R.
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Proof First we show that the result holds for the first part ... View full answer
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