Question: X[n] and y[n] are two real-valued, positive, finite-length sequences of length 256; i.e.,? x[n] > 0, 0 ? n ? 225, y[n] > 0, 0
X[n] and y[n] are two real-valued, positive, finite-length sequences of length 256; i.e.,?
x[n] > 0, 0 ? n ? 225,
y[n] > 0, 0 ? n ? 255,
x[n] = y[n] = 0, otherwise
r[n] denotes the linear convolution of x[n] and y[n]. R(ej?) denotes the Fourier transform of r[n]. Rs[k] denotes 128 equally spaced samples of R(ej?); i.e.,
Rs[k] R(ej?)|w=2?k/128,? ? ? ? ?k = 0. 1,?., 127.
Given x[n] and y[n], we want to obtain Rs[k] as efficiently as possible. The only modules available are those shown in Figure. The costs associated with each module are as follows:
Modules I and II are free.
Module III costs 10 units.
Module IV costs 50 units.
Module V costs 100 units.?
![Module I Module III $i{n] III s[n] 127 szln) s[n + 128r]](https://dsd5zvtm8ll6.cloudfront.net/si.experts.images/questions/2022/11/636a506e69ab2_790636a506e59a4c.jpg)
By appropriately connecting one or several of each module, construct a system for which the inputs are x[n] and y[n] and the output is Rs[k]. The important considerations are (a) whether the system works and (b) how efficient it is. The lower the total cost, the more efficient the system is.
Module I Module III $i{n] III s[n] 127 szln) s[n + 128r] ;[m]s2{n - m} (a) (c) Module IV Module II si[n] II IV s [n]. 0 s ns 127 0, otherwise s[n] 255 w (n] = $2[n} 2 slm}sz[n - m] m -0 (b) (d) Module V 127 s[n] S[k] = sIr]e2/128)nk n-0 (e)
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