Question: A 1.50-kg particle moves in the xy plane with a velocity of v = (4.20i 3.60j) m/s. Determine the angular momentum of the particle when

A 1.50-kg particle moves in the xy plane with a velocity of v = (4.20i ─ 3.60j) m/s. Determine the angular momentum of the particle when its position vector is r = (1.50i + 2.20 j) m.

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