Question: A particle with specific charge q/m moves in the region of space where there are uniform mutually perpendicular electric and magnetic fields with strength E
(a) The law of motion x (t) and y (t) of the particle; the shape of the trajectory;
(b) The length of the segment of the trajectory between two nearest points at which the velocity of the particle turns into zero; Fig. 3.104.
(c) The mean value of the particle's velocity vector projection on the x axis (the drift velocity).
E B
Step by Step Solution
3.34 Rating (166 Votes )
There are 3 Steps involved in it
a The equation of motion is Now m vx B So the equation becomes dr q EvxB dt 1320 KIZR k 0 0 B iByjBx ... View full answer
Get step-by-step solutions from verified subject matter experts
Document Format (1 attachment)
P-E-C-P (21).docx
120 KBs Word File
