Polonium 210 84 Po (atomic mass = 209.982 848 u) undergoes a decay. Assuming that all the
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Polonium 21084Po (atomic mass = 209.982 848 u) undergoes a decay. Assuming that all the released energy is in the form of kinetic energy of the a particle (atomic mass = 4.002 603 u) and ignoring the recoil of the daughter nucleus (lead 20682Pb, 205.974 440 u), find the speed of the a particle. Ignore relativistic effects.
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Since energy is released during the decay the combined mass of the lead 206 82 Pb daug...View the full answer
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