Question: Prove that is continuous on R2 and has first-order partial derivatives everywhere on R2, but f is not differentiable at (0, 0). (x, y)(0.0) (x,
.png)
is continuous on R2 and has first-order partial derivatives everywhere on R2, but f is not differentiable at (0, 0).
(x, y)(0.0) (x, y) = (0,0) f(x, y) = X2 +y2 0
Step by Step Solution
3.37 Rating (172 Votes )
There are 3 Steps involved in it
Clearly f is continuous and has firstorder partial derivatives at every point x y 0 ... View full answer
Get step-by-step solutions from verified subject matter experts
Document Format (1 attachment)
741-M-N-A-D-I (631).docx
120 KBs Word File
