Question: Prove the trigonometric integral identities (5.13). 0, k#1, 12. cos k x cos lx dx k=1=0. = k, (5.13) sin kx sin 1 x dx
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0, k#1, 12. cos k x cos lx dx k=1=0. = k, (5.13) sin kx sin 1 x dx =10, cos k x sin x dx = 0,
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