Question: [Pt(NH3)2Cl2] is found to exist in two geometric isomers designated I and II, which react with oxalic acid as follows: Comment on the structures of
[Pt(NH3)2Cl2] is found to exist in two geometric isomers designated I and II, which react with oxalic acid as follows:
Comment on the structures of I and II.
1+ H;C,O4 II + H;C,0, [Pt(NH;),C,0,] [Pt(NH3 )2(HC;04)2]
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Isomer I must be the cis isomer The chlorines must be ... View full answer
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