Reaction of 3,3-dimethyl-1-butene with hydrogen iodide yields two compounds A and B, each having the molecular formula C6H13I, in the ratio A:B = 90:10. Compound A, on being heated with potassium hydroxide in n-propyl alcohol, gives only 3, 3-dimethyl-1-butene. Compound B undergoes elimination under these conditions to give 2, 3-dimethyl-2-butene as the major product. Suggest structures for compounds A and B, and write a reasonable mechanism for the formation of each.