Question: Repeat Problem 94 with a second block having a mass of 5 kg and moving to the right at 3 m/s. Following same procedures one
Repeat Problem 94 with a second block having a mass of 5 kg and moving to the right at 3 m/s.
Following same procedures one obtains:
(a) Find the velocity vcm of the center of mass.
(b) Subtract vcm from the velocity of each block to find the velocity of each block in the center-of-mass reference frame.
(c) After they make an elastic collision, the velocity of each block is reversed in this frame. Find the velocity of each block after an elastic collision.
(d) Transform back into the original frame by adding vcm to the velocity of each block.
(e) Check your result by finding the initial and final kinetic energies of the blocks in the original frame
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a v cm 375 ms b u 3 125 ms u 5 075 ms c u 3 ... View full answer
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