Question: Show that if u, v Rn, then det (I + uvt) = 1 + vtu.

Show that if u, v ∈ Rn, then det (I + uvt) = 1 + vtu.

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Let be an eigenvalue of M I uvt with eigenvector x 0 Then x Mx I uvx x vx u Thus 21x vx u ... View full answer

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