Question: Show that the maximum value for 2py [Eq. (6.123)] is k3/2 -1/2e-1. Use Eq. (6.123) to plot the 2py contour for which = 0.316max.

Show that the maximum value for 2py [Eq. (6.123)] is k3/2 π-1/2e-1. Use Eq. (6.123) to plot the 2py contour for which ψ = 0.316ψmax.

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