A single isolated, large conducting plate (Fig ) has a charge per unit area sigma on its surface Because the plate is a conductor, the electric field at its surface is perpendicular to the surface and has magnitude E sigma 1108 0 (a) In Example 22 7 (Section 22 4) it was shown that the field caused by a large, uniformly charged sheet with charge per unit area sigma has magnitude E sigma 2 1108 0, exactly half as much as for a charged conducting plate Why is there a difference (b) Regarding the charge distribution on the conducting plate as being two sheets of charge (one on each surface), each with charge per unit area sigma , use the result of Example 22 7 and the principle of superposition to show that E 0 inside the plate and E sigma 1108 0 outside the plate E oleo E oleo

Question: A single isolated, large conducting plate (Fig.) has a charge per unit area σ on its surface. Because the plate is a conductor, the electric

A single isolated, large conducting plate (Fig.) has a charge per unit area σ on its surface. Because the plate is a conductor, the electric field at its surface is perpendicular to the surface and has magnitude E = σ /є0. (a) In Example 22.7 (Section 22.4) it was shown that the field caused by a large, uniformly charged sheet with charge per unit area σ has magnitude E = σ /2є0, exactly half as much as for a charged conducting plate. Why is there a difference? (b) Regarding the charge on the conducting plate as being two sheets of charge (one on each surface), each with charge per unit area σ, use the result of Example 22.7 and the principle of superposition to show that E = 0 inside the plate and E = σ /є0 outside the plate

E- oleo E= oleo.

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