Question: Solve LI + RI ' + I /C = E 0 e it , i = -1, by substituting l p =

Solve LI^∼" + RI^∼' + I^∼/C = E₀e^iωt, i = √-1, by substituting l_p= Ke^iωt(K unknown) and its derivatives and taking the real part l_p of the solution l^∼_p. Show agreement with (2), (4). Use (11) e^iωt= cos ωt + i sin ωt; cf. Sec. 2.2, and i² = -1.

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