Solve, showing details: y' 1 = y1 + 2y 2 + e 2t - 2ty' 2 = -y 2 + 1 + ty 1 (0) = 1, y 2 (0) = -4
Chapter 4, PROBLEM SET 4.6 #15
Solve, showing details:
y'1 = y1 + 2y2 + e2t - 2t
y'2 = -y2 + 1 + t
y1(0) = 1, y2(0) = -4
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Answer
y\'1 = 2.2 y2 y\'2 = -.25 y1 + 1.5 The solution of this system is .......…View the full answer
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