# Solve, showing details: y' 1 = y1 + 2y 2 + e 2t - 2ty' 2 = -y 2 + 1 + ty 1 (0) = 1, y 2 (0) = -4

Chapter 4, PROBLEM SET 4.6 #15

Solve, showing details:

y'_{1} = y1 + 2y_{2} + e^{2t} - 2t

y'_{2} = -y_{2} + 1 + t

y_{1}(0) = 1, y_{2}(0) = -4

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