Question: Solve, showing details: y' 1 = y1 + 2y 2 + e 2t - 2t y' 2 = -y 2 + 1 + t y

Solve, showing details:

y'1 = y1 + 2y2 + e2t - 2t
y'2 = -y2 + 1 + t
y1(0) = 1, y2(0) = -4


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