Question: Solve, showing details: y' 1 = y 2 + 6e 2t y' 2 = y 1 - e 2t y 1 (0) = 1, y

Solve, showing details:

y'1 = y2 + 6e2t
y'2 = y1 - e2t

y1(0) = 1, y2(0) = 0

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y1x x ex y2x x ex Which becomes y1 y2 6e2t y2 y1 6e2t Now we get a couple of equations We can use th... View full answer

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