Question: Solve the following initial value problems. y' 1 = 3y 1 + 2y 2 y' 2 = 2y 1 + 3y 2 y 1 (0)

Solve the following initial value problems.

y'1 = 3y1 + 2y2

y'2 = 2y1 + 3y2

y1(0) = 0.5, y2(0) = -0.5

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