Recalculate the Otto cycle in P16.5 using EQUIL2 to evaluate the conditions around the cycle. Do these calculations both with and without considering dissociation. How has the use of more accurate data, and a better evaluation of the combustion process affected the results? Is the effect of dissociation appreciable? Explain your reasoning. [47.98\%]

P16.5

Compare the air-standard cycle thermal efficiencies of an Otto cycle obtained by calculating the state points around the cycle with the value obtained from Eqn (3.16) for an 'engine' operating with a compression ratio, \(r\), of 15:1, and an air-fuel ratio, \(\varepsilon=28: 1\) The trapped conditions are \(1.0 \mathrm{bar}\) and \(27^{\circ} \mathrm{C}\). Assume \(Q_{p}^{\prime}=44000 \mathrm{~kJ} / \mathrm{kg}\), the specific heat capacity at constant volume, \(c_{\mathrm{v}}\), is \(0.721 \mathrm{~kJ} / \mathrm{kg} \mathrm{K}\), and \(\kappa=1.4\). The trapped conditions are 1 bar and \(27^{\circ} \mathrm{C}\). [66.1\%;65.62\%]

Transcribed Image Text:

R= K PO(-4) (P-R)da (16.16a) T (1-x) P=K'm m(po) (16.16b)