Under a similarity transformation with \(\mathbf{S}\), group members \(\mathbf{A}\) and \(\mathbf{B}\) transform as \(\mathbf{S A S}^{-1}=\mathbf{R}\) and \(\mathbf{S B S}{ }^{-1}=\mathbf{T}\). Show that \(\mathbf{S A B S}{ }^{-1}=\mathbf{R T}\).