Question: The differential equation y = 2ty + e t2 , y(0) = 5, has solution y = (t + 5)e t2 . In the following

The differential equation y′ = 2ty + e^t2, y(0) = 5, has solution y = (t + 5)e^t2. In the following table, fill in the second row with the values obtained from the use of a numerical method and the third row with the actual values calculated from the solution. What is the greatest difference between corresponding values in the second and third rows? ti Yi y 0 5 5 .2 5.412 .4 .6 .8 1

ti Yi y 0 5 5 .2 5.412 .4 .6 .8 1 1.2 1.4 1.6 1.8 2 382.2

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