Question: The differential equation y = et - 2y, y(0) = 1, has solution y = 1/3(2e -2t + et ). In the following table, fill

The differential equation y′ = et - 2y, y(0) = 1, has solution y = 1/3(2e-2t + et ). In the following table, fill in the second row with the values obtained from the use of a numerical method and the third row with the actual values calculated from the solution. What is the greatest difference between corresponding values in the second and third rows?0 1 y 1 .25 .8324 .50 .75 1 1.25 1.5 1.75

0 1 y 1 .25 .8324 .50 .75 1 1.25 1.5 1.75 2 2.4752

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