Consider the differential equation 4xu + 2u + u = 0. Given that cos x solves the
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Consider the differential equation 4xu′′ + 2u′ + u = 0. Given that cos √x solves the Given that cos √x solves the boundary value problem u(1/4) π2 = 0, u(π2) = −1, and sin √x solves the boundary value problem u(1/4 π2) = 1, u(π2) = 0, write down the solution to the boundary value problem u (1/4 π2) = −3, u(π2) = 7.
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