# In Example 9(a), change the coefficient of the first term from 20 to 5 and then factor. Data from Example 9(a) In factoring 20x 2 45, note a common factor of 5 in each term. Therefore, 20x 2

In Example 9(a), change the coefficient of the first term from 20 to 5 and then factor.

**Data from Example 9(a)**

In factoring 20x^{2} − 45, note a common factor of 5 in each term. Therefore, 20x^{2} − 45 = 5(4x^{2} − 9). However, the factor 4x^{2} − 9 itself is the difference of squares. Therefore, 20x^{2} − 45 is completely factored as 20x ^{2} − 45 = 5(4x^{2} − 9) = 5(2x + 3)(2x − 3)

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## To change the coefficient of the first term from 20 to 5 we need to factor out the greatest common …View the full answer

**Related Book For**

## Basic Technical Mathematics

**ISBN:** 9780137529896

12th Edition

**Authors:** Allyn J. Washington, Richard Evans

**Question Details**

Chapter #

**6**- Factoring and FractionsSection: Exercises 6.1

Problem: 3

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