In Example 9(a), change the coefficient of the first term from 20 to 5 and then factor. Data from Example 9(a) In factoring 20x 2 45, note a common factor of 5 in each term. Therefore, 20x 2

In Example 9(a), change the coefficient of the first term from 20 to 5 and then factor.


Data from Example 9(a)

In factoring 20x2 − 45, note a common factor of 5 in each term. Therefore, 20x2 − 45 = 5(4x2 − 9). However, the factor 4x2 − 9 itself is the difference of squares. Therefore, 20x2 − 45 is completely factored as 20x 2 − 45 = 5(4x2 − 9) = 5(2x + 3)(2x − 3)

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Related Book For  answer-question

Basic Technical Mathematics

ISBN: 9780137529896

12th Edition

Authors: Allyn J. Washington, Richard Evans

Question Details
Chapter # 6- Factoring and Fractions
Section: Exercises 6.1
Problem: 3
Posted Date: March 20, 2023 04:06:20