Perform the indicated operations for the resulting complex numbers if the given changes are made in the indicated examples of this section.

In Example 6, replace 2j with −2j and then find the roots.

Data from Example 6

Find the two square roots of 2j.
First, we write 2j in polar form as 2j = 2(cos 90° + j sin 90°). To find square roots, we use the exponent 1 2. The first square root is.

To find the other square root, we add 360° to 90°. This gives us

Therefore, the two square roots of 2j are 1 + j and −1 − j. We see in Fig. 12.19 that they are on a circle of radius √2 and 180° apart.

Transcribed Image Text:

(2j)¹/2 = 2/2 cos +jsin- 90° 2 90° 2 √2(cos 45° + jsin 45°) = 1 + j