Solve the given problems related to the indicated examples of this section

In Example 7, interchange 40% and 20% and then find the function.

Data from Example 7

A metallurgist melts and mixes m grams (g) of solder that is 40% tin with n grams of another solder that is 20% tin to get a final solder mixture that contains 200 g of tin. Express n as a function of m. See Fig. 3.4.

The statement leads to the following equation:

0.40m + 0.20n = 200

Because we want n = f (m), we now solve for n:

This is the required function. Note that neither m nor n can be negative. The domain is all values 0 ≤ m ≤ 500 g, since m must be greater than or equal to 0 g and less than or equal to 500 g. The range is all values 0 ≤ n ≤1000 g.

0.20n 200 - 0.40m n = 1000 - 2m