In Exercises show that the function represented by the power series is a solution of the differential
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In Exercises show that the function represented by the power series is a solution of the differential equation.
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x2n 4"(n!)² y = Σ (-1)". n=0 x²y" + xy + x²y = 0
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a y 1 y xy xy xy 11 12nx21 00 P 00 PT n0 n0 x 4 n n0 1 2n 2...View the full answer
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