In Exercises show that the function represented by the power series is a solution of the differential
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In Exercises show that the function represented by the power series is a solution of the differential equation.
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y = n=0 x2n 2" n!' y"-xy' - y = 0
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00 y n0 xan 2n y my y II 2nx2n1 2n n1 2n2n ...View the full answer
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